\magnification=1200 \nopagenumbers \vsize = 8.0 truein \hbox {~} \parindent=0pt {\centerline{\bf Interpretation of the visibility profiles for double sources}} \medskip The visibility function $V(u,v)$ from a circular source is proportional to the visibility of a unit point source, where the constant of proportionality is the flux (F) multiplied by the relative amplitude function $R(u,v)$. The relative amplitude is an exponential function of the wavenumber $k =\sqrt(u^2+v^2)$ and the area $A=\pi a^2$ of the source: $$ R = e^{-2\pi^2k^2a^2} = e^{-2\pi k^2 A} $$ \smallskip The visibilility of the circular source is therefore, $$ V=F R e^{i{\bf k}\cdot{\bf x}} \eqno{(1)} $$ where ${\bf x}$ is the vectorial displacement of the source from map center. For the two-source case, let the map center be at the geometrical midpoint of the two sources, which are then located at $-x_1$ and $x_1$. The visibility is then $$ V = R_1\ F_1 e^{-i\bf{k}\cdot \bf{x_1}} + R_2\ F_2 e^{i\bf{k}\cdot \bf{x_1}} \eqno{(2)} $$ The amplitude $|V|$ may be written as: $$ |V| = [(R_1F_1)^2+(R_2F_2)^2 + 2(R_1 F_1)(R_2 F_2) cos(2{\bf k}\cdot {\bf x_1})]^{1/2} \eqno{(3)} $$ $$ = [(R_1 F_1-R_2 F_2)^2 + 4(R_1 F_1)(R_2 F_2) cos^2({\bf k}\cdot {\bf x_1})]^{1/2} \eqno{(3')} $$ During a 4 s time interval, the RHESSI, $\bf{k}$ vector rotates $360^{\circ}$, and the visibility is modulated by this rotation. For a single relatively coarse subcollimator for which $|k| x_1 < \pi/2$, the amplitude $|V|$ varies nearly sinusoidally as a function of position angle with a minimum when $\bf{k}$ is parallel to $\bf{x_1}$ and a maximum when ${\bf k}\cdot {\bf x_1} =0$. The position angle locations of the minima give the position angle of the line between the sources. The maxima are $90^{\circ}$ away. \smallskip This gives a relation between $F_1/F_2$ and the source areas $A_1$ and $A_2$ (we assume $A_1 > A_2$): $$ (F_1/F_2)e^{-2*\pi k^2[(A_1-A_2)} = (1-|V|_{min}/|V|_{max})/(1+|V|_{min}/|V|_{max}) \eqno{(4)} $$ For those (finer) grids for which $|k| x_1 \ge \pi/2$, the amplitude $|V|$ can have more than one extremum when ${\bf k}\cdot {\bf x_1} = \pi/2, 3\pi/2,\dots$. \smallskip Taking the ratio of equation (4) for two different values of $|k|$ (i.e two different subcollimators) makes the flux ratio $F_1/F_2$ cancel out, and the quantity $(A_1-A_2)$ can be determined. After that, the flux ratio may be determined from equation (4) for one of the subcollimators. \end